1-(1/(x+1)^2)=0

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Solution for 1-(1/(x+1)^2)=0 equation: 


D( x )

(x+1)^2 = 0

(x+1)^2 = 0

(x+1)^2 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

1-(1/((x+1)^2)) = 0

1-(x+1)^-2 = 0

1-1/((x+1)^2) = 0

(1*(x+1)^2)/((x+1)^2)-1/((x+1)^2) = 0

1*(x+1)^2-1 = 0

x^2+2*x = 0

x^2+2*x = 0

x*(x+2) = 0

x+2 = 0 // - 2

x = -2

x*(x+2) = 0

(x*(x+2))/((x+1)^2) = 0

(x*(x+2))/((x+1)^2) = 0 // * (x+1)^2

x*(x+2) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x )

x = 0

x in { -2, 0 }

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